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CBSE Maths · Class 10

Chapter 11: Areas Related to Circles

Name: ________________________
Date: ______________
Marks: ____ / 10

Circumference and area of a circle, area of a sector and segment, combined figures.

Questions

  1. Circumference: r=21r = 21 (π=22/7\pi = 22/7).
  2. Sector area: θ=90,r=10\theta = 90^\circ, r = 10.
  3. Arc length: θ=45,r=14\theta = 45^\circ, r = 14.
  4. Radius when circumference =88= 88.
  5. Area of annulus R=10,r=7R = 10, r = 7.
  6. Minor segment area r=10,θ=60r = 10, \theta = 60^\circ.
  7. Wheel makes 200200 revolutions to cover 8888 m. Diameter?
  8. Area of a quadrant of a circle with r=14r = 14.
  9. Perimeter of a sector: r=21r = 21, θ=60\theta = 60^\circ.
  10. Area of a shaded region: circle of radius 77 inscribed in a square of side 1414.

Extra Practice (Optional)

  • Area of the sector θ=120\theta = 120^\circ, r=6r = 6.
  • Area of shaded region between two concentric circles.
  • Circumference of a semicircle with r=14r = 14.
  • Length of chord subtending 9090^\circ at centre, r=10r = 10.
  • Radius of circle with area =616= 616 cm2^2.

Answer Key (For Teachers)

  1. Answer: 132132 cm.
    Working: 2πr2\pi r.
  2. Answer: 25π25\pi.
    Working: Quarter area.
  3. Answer: 1111.
    Working: Formula.
  4. Answer: 1414.
    Working: 2πr=882\pi r = 88; r=887/44r = 88\cdot 7/44.
  5. Answer: 51π51\pi.
    Working: π(10049)\pi(100-49).
  6. Answer: 50π3253\dfrac{50\pi}{3} - 25\sqrt 3.
    Working: Sector - equilateral triangle.
  7. Answer: 1414 cm.
    Working: C=88/200=0.44C = 88/200 = 0.44; d=C/πd = C/\pi.
  8. Answer: 154154 cm2^2.
    Working: πr2/4\pi r^2/4.
  9. Answer: 6464 cm.
    Working: Perim =2r+= 2r + arc =42+22= 42 + 22.
  10. Answer: 4242 cm2^2.
    Working: Shaded == square - circle =196154= 196 - 154.
Gyaan Maths · CBSE Class 10 · Chapter 11
Gyaan Maths — CBSE Class 6-10, built for board-toppers.
v1.1 · Feb 2026