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Class 10 · Mathematics (Basic) · Unit 1: Real Numbers

Proving Irrationality

Lesson 3 of 5
To prove p\sqrt{p} (with pp prime) is irrational, assume p=a/b\sqrt{p} = a/b with gcd⁡(a,b)=1\gcd(a,b)=1. Squaring gives pb2=a2pb^2 = a^2, so p∣a2⇒p∣ap\mid a^2 \Rightarrow p\mid a. Write a=pka = pk: then b2=pk2b^2 = pk^2, so p∣bp\mid b. This contradicts gcd⁡(a,b)=1\gcd(a,b)=1.
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v1.1 · Sept 2026