g
Gyaan Maths
CBSE · Class 6-10
Back to chapter
CBSE Maths · Class 9

Chapter 11: Surface Areas and Volumes

Name: ________________________
Date: ______________
Marks: ____ / 10

Cuboid, cube, right circular cylinder, cone, sphere, and hemisphere: surface areas and volumes.

Questions

  1. SA of a sphere radius 77.
  2. Volume of cone r=3,h=4r = 3, h = 4.
  3. Volume of hemisphere radius 66.
  4. CSA of cylinder r=5,h=14r = 5, h = 14.
  5. TSA of cube edge 55.
  6. Volume of cylinder r=7,h=10r = 7, h = 10.
  7. Slant height of cone r=3,h=4r = 3, h = 4.
  8. TSA of hemisphere radius 77.
  9. Cuboid l=5,b=4,h=3l=5, b=4, h=3: TSA.
  10. A cylindrical tank r=1.4r = 1.4 m, h=3h = 3 m: capacity in litres.

Extra Practice (Optional)

  • Volume of sphere r=5r = 5.
  • TSA of cuboid l=8,b=6,h=5l=8, b=6, h=5.
  • Vol of cone r=6,h=8r = 6, h = 8.
  • Volume of hemisphere r=10.5r = 10.5.
  • SA of a football (sphere) radius 1010 cm.

Answer Key (For Teachers)

  1. Answer: 616616.
    Working: 4πr24\pi r^2.
  2. Answer: 12π12\pi.
    Working: 13πr2h\tfrac{1}{3}\pi r^2 h.
  3. Answer: 144π144\pi.
    Working: 23πr3\tfrac{2}{3}\pi r^3.
  4. Answer: 440440.
    Working: 2πrh2\pi rh.
  5. Answer: 150150.
    Working: 6a26a^2.
  6. Answer: 15401540.
    Working: πr2h\pi r^2 h.
  7. Answer: 55.
    Working: Pythagoras.
  8. Answer: 462462.
    Working: 3πr23\pi r^2.
  9. Answer: 9494.
    Working: 2(20+12+15)=942(20+12+15) = 94.
  10. Answer: ≈18480\approx 18480 L.
    Working: Vol =227⋅1.96⋅3≈18.48= \tfrac{22}{7}\cdot 1.96\cdot 3 \approx 18.48 m3=18480^3 = 18480 L.
Gyaan Maths · CBSE Class 9 · Chapter 11
Gyaan Maths — CBSE Class 6-10, built for board-toppers.
v1.1 · Feb 2026