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Gyaan Maths
CBSE · Class 6-10
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CBSE Maths · Class 8

Chapter 8: Comparing Quantities

Name: ________________________
Date: ______________
Marks: ____ / 10

Percentages, profit/loss, discount, compound interest.

Questions

  1. SI on \rupee5000\rupee 5000 at 8%8\% for 22 years.
  2. CI on \rupee5000\rupee 5000 at 10%10\% p.a. for 22 years.
  3. MP \rupee1200\rupee 1200, successive discounts 10%10\% and 5%5\%. SP?
  4. P=1000,R=10%,n=2P = 1000, R = 10\%, n = 2: CI.
  5. Discount of 15%15\% on MP ₹800₹800: SP.
  6. If CP =₹500=₹500, profit 20%20\%: SP.
  7. A quantity increased 20%20\% then 10%10\%: overall %\% change.
  8. CI on P=5000,R=8%,n=1P = 5000, R = 8\%, n = 1.
  9. Population grows 5%5\% annually; find population after 22 years starting at 1000010000.
  10. Convert profit %\% to CP given SP and profit.

Extra Practice (Optional)

  • A camera bought \rupee5000\rupee 5000 sold at \rupee4600\rupee 4600. Loss?
  • Difference between SI and CI on \rupee10000\rupee 10000 at 10%10\% for 22 y.
  • Marked price if SP =\rupee900=\rupee 900 after 10%10\% discount.

Answer Key (For Teachers)

  1. Answer: \rupee800\rupee 800.
    Working: 5000⋅8⋅2100\dfrac{5000\cdot 8\cdot 2}{100}.
  2. Answer: \rupee1050\rupee 1050.
    Working: A=5000(1.1)2=6050A=5000(1.1)^2=6050; CI=1050CI=1050.
  3. Answer: \rupee1026\rupee 1026.
    Working: After 10%10\%: 10801080; after 5%5\%: 10261026.
  4. Answer: 210210
    Working: A=1000(1.1)2=1210A = 1000(1.1)^2 = 1210; CI =210= 210.
  5. Answer: ₹680₹680
    Working: 800⋅0.85800\cdot 0.85.
  6. Answer: ₹600₹600
    Working: 500⋅1.2500\cdot 1.2.
  7. Answer: 32%32\%
    Working: 1.2×1.1=1.321.2\times 1.1 = 1.32.
  8. Answer: ₹400₹400
    Working: SI=CI=400SI = CI = 400 when n=1n=1.
  9. Answer: 1102511025
    Working: 10000(1.05)2=1102510000(1.05)^2 = 11025.
  10. Answer: As formula.
    Working: Use formula CP=SP/(1+p/100)CP = SP/(1 + p/100).
Gyaan Maths · CBSE Class 8 · Chapter 8
Gyaan Maths — CBSE Class 6-10, built for board-toppers.
v1.1 · Feb 2026