CBSE Maths · Class 10
Chapter 5: Arithmetic Progressions
Name: ________________________
Date: ______________
Marks: ____ / 10
Sequences where each term differs from the previous by a fixed common difference; formulas for the n-th term and sum of the first n terms.
Questions
- S20 of 5,8,11,…
- Which term of 21,18,15,… is −81?
- Find a25 of 2,5,8,…
- Sum of first 50 natural numbers.
- an of AP 10,7,4,… when n=15.
- How many terms of 2,4,6,… add to 110?
- Three numbers in AP have sum 24 and product 440.
- Which term of the AP 3,8,13,… is 78?
- Sum of first n terms is 3n2+5n. Find nth term.
- The 7th term of an AP is 34 and 13th is 64. Find the AP.
Extra Practice (Optional)
- Sum of first 100 multiples of 3.
- If a3=5,a7=9, find AP.
- Middle term of an AP with 9 terms.
- Sum of first 50 even numbers.
- S20−S10 for an AP with a=2,d=3.
Answer Key (For Teachers)
- Answer: 670.
Working: a=5,d=3; S20=10(10+57). - Answer: 35th.
Working: Set 21+(n−1)(−3)=−81. - Answer: 74.
Working: 2+24⋅3. - Answer: 1275.
Working: n(n+1)/2. - Answer: −32.
Working: a=10,d=−3; a15=10+14(−3). - Answer: 10.
Working: Sn=n(n+1)=110. - Answer: 5,8,11.
Working: Take a−d,a,a+d; 3a=24,a=8; then d2=9. - Answer: 16th.
Working: 3+(n−1)5=78⇒n=16. - Answer: 6n+2.
Working: an=Sn−Sn−1. → =(3n2+5n)−(3(n−1)2+5(n−1))=6n+2. - Answer: 4,9,14,…
Working: a+6d=34,a+12d=64. → Subtract: 6d=30⇒d=5,a=4.
Gyaan Maths · CBSE Class 10 · Chapter 5